25x+275=16x^2

Solution for 25x+275=16x^2 equation:

25x+275=16x^2

We move all terms to the left:

25x+275-(16x^2)=0

determiningTheFunctionDomain
-16x^2+25x+275=0

a = -16; b = 25; c = +275;
Δ = b2-4ac
Δ = 252-4·(-16)·275
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18225}=135$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-135}{2*-16}=\frac{-160}{-32}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+135}{2*-16}=\frac{110}{-32}
=-3+7/16
$